5x^2+5x-810=0

Solution for 5x^2+5x-810=0 equation:

5x^2+5x-810=0

a = 5; b = 5; c = -810;
Δ = b2-4ac
Δ = 52-4·5·(-810)
Δ = 16225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{16225}=\sqrt{25*649}=\sqrt{25}*\sqrt{649}=5\sqrt{649}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(5)-5\sqrt{649}}{2*5}=\frac{-5-5\sqrt{649}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(5)+5\sqrt{649}}{2*5}=\frac{-5+5\sqrt{649}}{10}
$